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Re: fsck and async mode



Moshe Zadka wrote:

> On Sun, 7 May 2000, Omer wrote:
>
> > (define linux
> >  (lambda question t))
>
> hmmmmm.....
>
> Didn't you mean
>
> (define linux
>   (lambda question #t))
>
> ?
>
> "t" is just a symbol like any other, while #t is the "canonical truth
> value"

Wrong - in R4RS t is #t and nil is #f. R5RS is not there yet, and it
seems that it will never be.

And to enforce your first presonal impression:

(define linux
  (lambda q
    (lambda (x)
      ((lambda (y) x)))))

And of course lambda should be printed out as lambda symbol!!

>
> --
> Moshe Zadka <moshez@math.huji.ac.il>
> http://www.oreilly.com/news/prescod_0300.html
> http://www.linux.org.il -- we put the penguin in .com
>
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--
Omer Mussaev    051-308-214   mailto:omerm@mercury.co.il
systems programmer, Mercury Interactive/RND/Conduct/core




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