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Re: fsck and async mode
Moshe Zadka wrote:
> On Sun, 7 May 2000, Omer wrote:
>
> > (define linux
> > (lambda question t))
>
> hmmmmm.....
>
> Didn't you mean
>
> (define linux
> (lambda question #t))
>
> ?
>
> "t" is just a symbol like any other, while #t is the "canonical truth
> value"
Wrong - in R4RS t is #t and nil is #f. R5RS is not there yet, and it
seems that it will never be.
And to enforce your first presonal impression:
(define linux
(lambda q
(lambda (x)
((lambda (y) x)))))
And of course lambda should be printed out as lambda symbol!!
>
> --
> Moshe Zadka <moshez@math.huji.ac.il>
> http://www.oreilly.com/news/prescod_0300.html
> http://www.linux.org.il -- we put the penguin in .com
>
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--
Omer Mussaev 051-308-214 mailto:omerm@mercury.co.il
systems programmer, Mercury Interactive/RND/Conduct/core
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